((3+7i)/2)^2-3((3+7i)/2)+4=0

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Solution for ((3+7i)/2)^2-3((3+7i)/2)+4=0 equation: 


i in (-oo:+oo)

((7*i+3)/2)^2-(3*((7*i+3)/2))+4 = 0

((7*i+3)/2)^2+(-3/2)*(7*i+3)+4 = 0

((7*i+3)^2)/(2^2)-3/2*(7*i+3)+4 = 0

((7*i+3)^2)/(2^2)+(-3/2*2^2*(7*i+3))/(2^2)+(4*2^2)/(2^2) = 0

(7*i+3)^2-3/2*2^2*(7*i+3)+4*2^2 = 0

49*i^2-9+16 = 0

49*i^2+7 = 0

(49*i^2+7)/(2^2) = 0

(49*i^2+7)/(2^2) = 0 // * 4

49*i^2+7 = 0

49*i^2 = -7 // : 49

i^2 = -1/7

i belongs to the empty set

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